Reports 1-1 of 1 Clear search Modify search
Interferometer_sensitivity_studies (General)
ruggi, vajente - 12:58 Wednesday 22 July 2009 (23865) Print this report
Sensitivity vs finesse asymetry
The dipendence of the sensitivity from the finesse asymmetry is one more time quite evident. In fig 1 we see that during the afternoon and the night the parameters sensitive to lensing effects (B1_DC, B5_2f_ACq) were almost stable, while the etalon was still going on. The horizon was much better for negative values of finesse asymmetry.
As observed by Edwige, a general increase of the floor is the biggest effect in the sensitivity(fig 2).
The noise budget is able to explain very well the origin of the problem: comparing the two conditions (dF/F=-0.03, fig 3; dF/F=0.034, fig 4), we see that the contribution of B5 shot noise is much larger when the finesse asymmetry is positive. The contribution to the horizon is about 1 Mpc both in the actual sensitivity and in the predicted noise.
Probably the coupling of common noises (Common Mode Rejection Factor) is lower when the finesse asymmetry is negative because there is a compensation effect between the contribution from finesse aymmetry and the one from asymmetry of losses.
Images attached to this report
Comments to this report:
bondu - 15:51 Wednesday 22 July 2009 (23870) Print this report
Indeed, the asymmetry factor (F_asym = h / (dnu/nu) )
is
F_asym = ABS( (dF/F) 1/(1+i f/f_rec)
+ (dzeta/zeta) f_p/f_rec (1+i f/f_p)/(1+i f/f_p) )
does predict a compensation in low/medium band on the detector bandwidth.
In this formula,
- F is the finesse, dF the finesse asymmetry;
- f_p is the arm cavity pole (500 Hz) and f_rec the recycling cavity pole (8 Hz)
- zeta is the arm amplitude reflectivity at resonance, and dzeta its asymmetry, so that dzeta/zeta = dR/4 = (+/-) sqrt((1-C)/2), where the sign depends where the losses are higher, and the contrast defect the one for the TEM00 after OMC.


Comments to this report:
bondu - 18:04 Wednesday 02 September 2009 (24541) Print this report
There is a mistyping: the second term of the asymmetry begins with dzeta/2, not dzeta/zeta.
Search Help
×

Warning

×